gyre wrote:13 times the load is 13 times the load.
If you aren't using excessive power on the LEDs, your only improvement is to eliminate or minimize the resistor size.
Are you going to match the LED required voltage as closely as possible with the batteries?
Savannah wrote:It sounds freaky & wrong, so you need to do it.
gyre wrote:13 times the load is 13 times the load.
gyre wrote:If you aren't using excessive power on the LEDs, your only improvement is to eliminate or minimize the resistor size.
gyre wrote:Are you going to match the LED required voltage as closely as possible with the batteries?
Savannah wrote:It sounds freaky & wrong, so you need to do it.
gyre wrote:13 strings = 13 x 1 string's load.
Don't know why voltage is relevant here.
Without matching voltage, the series is used, maybe for no reason.
Very much to be avoided.
What is the pack voltage?
Savannah wrote:It sounds freaky & wrong, so you need to do it.
gyre wrote:Why is the pack voltage locked?
Savannah wrote:It sounds freaky & wrong, so you need to do it.
gyre wrote:Why is the pack 8 batteries?
There is a choice.
Savannah wrote:It sounds freaky & wrong, so you need to do it.
Savannah wrote:It sounds freaky & wrong, so you need to do it.
junglesmacks wrote:
http://picprojects.org.uk/projects/ledc ... m#Firmware
This gives a basic trigger signal to 8 LEDs. The plan is to use NPN power transistors to use those trigger signals to trigger a string of 24 LEDs on each of the 8 channels. So yeah, the board runs off of 12v.. and then each string is jumped by the same 12v source via transistors.
junglesmacks wrote:DOH!
Of course, now after I've spent $60 on parts and supplies, I find someone with exactly what I'm trying to build. FML.
http://www.digitallighting.com/animatio ... /bcser.htm
I just spoke with these guys, and they said that they supply to a number of Burning man art cars. Check em out and maybe do something cool for next year..
Savannah wrote:It sounds freaky & wrong, so you need to do it.
junglesmacks wrote:Yes, you can run multiple colors off of the same channel. What you would do, is make a series string of just that color and then parallel it in with the other string. For example.. say you had a 12v source, and you wanted to run 10 red LEDs and 10 green LEDs off of the same channel. You would make 2 strings of 5 red LEDs (assuming they want 2v forward voltage) and then 4 strings of green LEDS ( assuming say a 3.3v forward volatage, 3 x 3 LEDs on ones and then 1 x 1 LED on another). Parallel those into the channel, and they are both taking the 12v.

Theres Always One wrote:junglesmacks wrote:Yes, you can run multiple colors off of the same channel. What you would do, is make a series string of just that color and then parallel it in with the other string. For example.. say you had a 12v source, and you wanted to run 10 red LEDs and 10 green LEDs off of the same channel. You would make 2 strings of 5 red LEDs (assuming they want 2v forward voltage) and then 4 strings of green LEDS ( assuming say a 3.3v forward volatage, 3 x 3 LEDs on ones and then 1 x 1 LED on another). Parallel those into the channel, and they are both taking the 12v.
The sum of the forward voltages must not exceed the voltage of the power supply.
So... 1 purple LED with a forward voltage of 3.6v needs a 3.6v power supply. 6 LED's = 6 x 3.6 = 21.6v power supply?! What am I not seeing here? Because you are talking about running 10 red off one 12 power supply.
Savannah wrote:It sounds freaky & wrong, so you need to do it.
junglesmacks wrote:Theres Always One wrote:junglesmacks wrote:Yes, you can run multiple colors off of the same channel. What you would do, is make a series string of just that color and then parallel it in with the other string. For example.. say you had a 12v source, and you wanted to run 10 red LEDs and 10 green LEDs off of the same channel. You would make 2 strings of 5 red LEDs (assuming they want 2v forward voltage) and then 4 strings of green LEDS ( assuming say a 3.3v forward volatage, 3 x 3 LEDs on ones and then 1 x 1 LED on another). Parallel those into the channel, and they are both taking the 12v.
The sum of the forward voltages must not exceed the voltage of the power supply.
So... 1 purple LED with a forward voltage of 3.6v needs a 3.6v power supply. 6 LED's = 6 x 3.6 = 21.6v power supply?! What am I not seeing here? Because you are talking about running 10 red off one 12 power supply.
Yes.. if you wanted to run 6 of those purple LEDs in a series, you would need at least a 21.6v power supply. That's why if you were running say a 12v power supply, you would use them in strings of 3 connected in a series, and then parallel those all together. Use that wiring schematic generator to test it out.
I was using 10 red LEDs with a forward voltage of 2v-2.2v as an example. If you were using a 12 volt source, you would run 2 series strings of 5 LEDS each, and them parallel them to the battery. That way, they battery would still only see no more than 12v of draw. Each string of 5 LEDs would be 2v + 2v + 2v + 2v + 2v = 10v.
You've got this..![]()
By the way.. not sure how you are planning on running 18-24v from your battery pack? I mean.. you could put 2 - 9 volt transistor batteries in series and that would give you 18v.. true. Just wouldn't have much mAh with those two little guys.
Theres Always One wrote:Ugh. I just ordered most of my LED's. They are all in the 20-25 mA range and the orange is 30 mA.
Then I'm reading this document to figure out the NPN transistor and it is talking about how these LED's require something beyond what an NPN transistor is capable of and it should not be used with these LED's.
http://picprojects.org.uk/projects/inf/drivingLEDs.pdf
I think I'm going to cancel the order for now and see if I can find LED's that use less mA. Or I don't know. Am I worried over nothing?
The document seems to be based off the assumption that LED's are going to be drawing 15 mA. But, from what I've seen, pretty much everything out there is "super high bright" and in the 20-30 mA range.
Savannah wrote:It sounds freaky & wrong, so you need to do it.
junglesmacks wrote:
All LEDs except the super brights should be 20 mA. Where are you getting them from? I picked up a bunch from Ebay super duper cheap.. and they are awesome. Tested them all and they kick butt. Do some Ebay searching.
Here is a link to the orange ones that I bought 25 for $1.50 with free shipping: http://cgi.ebay.com/ws/eBayISAPI.dll?Vi ... K:MEWNX:IT
There are all colors available.. just search.
In a conversation with Pete who created that pic board and website that you are quoting, he said that you don't have to run the LEDs at the stated mA requirement. You can get away with running 20 mA LEDs at 15, and the 30 mA "superbrights" at 20 mA if you are concerned with battery power.
You would also want to run either all super bight 30 mA models or the normal 20 mA models or else some will be brighter than others.
ALSO.. I was advised to use MOSFETs, not the NPN transistors die to the fact that they have higher power handling and dissipate less power. Use a MOSFET.
Savannah wrote:It sounds freaky & wrong, so you need to do it.
Theres Always One wrote:I got my LED's from Niktronix. http://www.niktronixonline.com/5mm_LED_ ... owslow.htm
Savannah wrote:It sounds freaky & wrong, so you need to do it.
junglesmacks wrote:These guys are a great source for electrical components: http://www.allelectronics.com/
MOSFETs are pretty simple things, really. 3 pins. You hook one pin up to (+), one to (-). When the middle pin gets juice, it flips the switch and completes the circuit. It's just a simple relay.
There are two ways in which a MOSFET can function. The first is known as depletion mode . When there is no voltage on the gate, the channel exhibits its maximum conductance . As the voltage on the gate increases (either positively or negatively, depending on whether the channel is made of P-type or N-type semiconductor material), the channel conductivity decreases. The second way in which a MOSFET can operate is called enhancement mode . When there is no voltage on the gate, there is in effect no channel, and the device does not conduct. A channel is produced by the application of a voltage to the gate. The greater the gate voltage, the better the device conducts.
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